One possible way is to figure out the operating pressure first. Turn down a reg until the cyclone begins to function erratically or not at all. That will be the minimum pressure that it needs at the current volume it's receiving. Chrono a bunch of shots to see the gun's current velocity at that configuration.
Then tape off the cyclone/RT port on the powertube to prevent any air loss from it. Re-chrono the gun and see what velocity increase exists due to the increase in volume.
Here's where I get lost because I'm not good with gaseous physics. A paintball requires a certain amount of pressure and volume to achieve a certain velocity. If we know the difference in velocity and the pressure, shouldn't be able to figure out the change in volume? If there are no other factors being introduced by taping off the port, that would be the volume that is normally given to the Cyclone. My question is how do we figure that out?
I did a little Wiki on this but not sure if I got the equations correct. Force equals pressure times area (or in our case volume)(F=p*V). Force also equals mass times acceleration (F=ma). If we do a little substitution, that would mean that pV=ma. To find the volume, that would be V=(ma)/p, correct? To get the acceleration, we need to figure out the amount of time it took to travel to the chrono. If we know the velocity, we divide it by the distance from one light sensor to the other on a shooting chrony. We then plug that in and it should give us the acceleration. Is all of this correct or did I go wrong someplace?
Edited by Lord Odin, 30 December 2008 - 07:28 PM.